Answer:
a) 96m
b) 2 m/s^2
Step-by-step explanation:
The distance travelled in a velocity time graph as shown in the image is the area of the shape. As such, considering the first 14 seconds, the distance covered will be computed by finding the area of the shape.
Note that the shape to be considered ends t the 14 seconds mark. This shape is a trapezium. The area of a trapezium is given as
A = 1/2(a + b) h
where a and b are the parallel sides of the trapezium and h is the height As such, the distance covered in the first 14 seconds
= 1/2 (14 + 10) * 8
= 4 * 24
= 96m
The acceleration after 4 seconds
Acceleration is the rate of change of velocity with time, at time 0 second, the velocity is also 0 but at time 4 seconds, the velocity is 8 m/s hence, the acceleration after 4 seconds
= 8/4
= 2 m/s^2
Answer:
Turtle = 11 m / min
Snail = 1 m / min
Total approach speed = 12 m/min
360 m / (12 m/min) = 30 min
Separation is 30 min at assumed speed of 1 m/min
But we know the separation is 40 min
So turtle moves at 3/4 * 11 m / min = 33 m/ 4 min
Snail moves at 3/4 * 1 m /min = 3/4 m / mi
Total approach speed = (33 + 3) / 4 = 9 m / min
So in 40 min
9 m / min * 40 min = 360 m
(Leaving out those units, they approach at 12 * unit of speed)
So the unit of speed has to be 360 m / 40 min = 9 m / min
Answer:
4c+5
Step-by-step explanation:
(c-4)+(3c+9)=c-4+3c+9=c+3c-4+9=4c-4+9=4c+5
Comparing 1/4 and 1/3 Draw a picture of these 2 fractions. You would see that 1/3 is bigger that 1/4.
Final Answer: 1/3 of 12
Hope I helped!
Let

be the

th partial sum of a geometric sequence with common ratio

and first term

. So the sequence is

, and

is

Multiplying both sides by

gives

and subtracting

from

gives



If

, then

as

and so the sum approaches