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storchak [24]
3 years ago
11

105,159 rounded to the nearest ten thousand

Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0
If you look at the hundereds place you see it is under the number 5 which means you would drop 1, 5, & 9 and the answer would be 105,000. If the number was above 5 you would have had to make it 106,000.

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For question 10e I wrote my answer as t=19, is that correct?
garri49 [273]

Answer:

1/19

Step-by-step explanation:

3(7) -2 = 19, this would be g(7) but they want g^-1 (7) so you need the inverse of your answer:
1/19.

HOPE THIS HELPS & MAKES SENSE!!!

3 0
2 years ago
Very Confused please help!
Nataly_w [17]
We know that<span>
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. 
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that</span>
<span> Circle 1 is centered at (5,8) and has a radius of 8 centimeters
 Circle 2 is centered at (1,-2) and has a radius of 4 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
the transformation has the following rule</span>
(x,y)--------> (x-4,y-10)
so
(5,8)------> (5-4,8-10)-----> (1,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
<span>A dilation is needed to decrease the size of circle 1 to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 4/8----> 0.5

radius circle 1 will be=8*scale factor-----> 8*0.5-----> 4 cm
radius circle 1 is now equal to radius circle 2 

<span>A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

the answer is
</span>
</span>The circles are similar because you can translate Circle 1 using the transformation rule (x-4,y-10) and then dilate it using a scale factor of (0.5)
4 0
3 years ago
An item was sold at a loss of 20%. Had it been sold for Rs 3000more then the profit would have been 10%. What is the cost price
vagabundo [1.1K]

Answer:

Cost Price = Rs 10000

Step-by-step explanation:

Assume:

Cost of the item = x

Item was sold at a loss of 20%:

Loss = 20% of x = 0.2x

Item sold = x - 0.2x = 0.8x

Item sold at a profit of 10%:

Profit = 10% of x = 0.1x

item sold = x + 0.1x = 1.1x

Solve:

Difference = 1.1x - 0.8x = 0.3x

0.3x = Rs 3000

x = Rs 3000 ÷ 0.3

x = Rs 10000

3 0
3 years ago
What is required in aerobic respiration?<br>​
likoan [24]
O2, or Oxygen, and C6H12O6, or glucose.
6 0
3 years ago
F(x) = x^2 - 16 What are the solutions for x when f of x equals 9?
andrey2020 [161]

Answer:

65

Step-by-step explanation:

5 0
2 years ago
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