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sergejj [24]
4 years ago
12

Decimals equivalent to 7/18​

Mathematics
2 answers:
natita [175]4 years ago
5 0
0.3889 I’m pretty sure that this is equivalent to 7/18
irinina [24]4 years ago
4 0

Answer:

0.38888....

Step-by-step explanation:

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Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
A survey of 100,000 adults found that 5% of Americans walk to work. Which of the following could be used to simulate the results
aalyn [17]

Answer:

A I think im fairly certain

Step-by-step explanation:

3 0
3 years ago
Yes help me for this maths questions
Elenna [48]
154cm squared this is the only right answer
3 0
3 years ago
Boston, Massachusetts had a population of 617,594 people during January 1 2010, and 675,647 people on January 1 2020.
tigry1 [53]

Answer:

  • See below

Step-by-step explanation:

<u>Exponential function is:</u>

  • y = abˣ

<u>If we consider the time difference in years as x and the initial population as a, then we get:</u>

  • 675647 = 617594*b¹⁰

<u>Find the value of b:</u>

  • b¹⁰ = 675647/617594
  • b¹⁰ = 1.09399864636
  • b = 1.09399864636^(1/10)
  • b = 1.009 (rounded)

<u>The equation we got is:</u>

  • y = 617594*1.009ˣ

Here we have y- population after x years since 2010, x - the number of years since 2010 and 1.009 is the population growth rate.

5 0
2 years ago
Please answer the simple math question
Shtirlitz [24]

Answer:

5y - 5b

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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