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marysya [2.9K]
3 years ago
14

1. Ashton rode his bicycle 3.25 miles in 12 minutes. What was Ashton's average rate in miles per hour

Mathematics
1 answer:
Contact [7]3 years ago
6 0

Answer: the answer is 3.6 mph

Step-by-step explanation: to find the average speed you need to divide your total distance by total time. Im this case you need to divide 12 by to find the average speed you need to divide your total distance by total time. Im this case you need to divide 12 by 3.25

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The table represents an exponential function.
devlian [24]
Hello,
f(1)=2\\
f(2)= \dfrac{2}{5} =2*5^{-1}\\
f(3)= \dfrac{2}{25} =2*5^{-2}\\
f(4)= \dfrac{2}{125} =2*5^{-3}\\\\

\boxed{f(x)= 2*5^{-x}} \\



4 0
3 years ago
Heyy! i’ll give brainliest please help
ipn [44]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Solve for the indicated variable in the parentheses<br><br> P = IRT Solve for (T)
KATRIN_1 [288]
P = IRT 

T=P/(IR)

hope helped 
8 0
3 years ago
Joe collected 94 stamps altogether. He collected 27 in April and 34 in May. How many did he collect in June?
stepan [7]

Answer:

33

Step-by-step explanation:

From what we know in April and May combined Joe has collected 61 stamps (27+34=61). To then work out how many Joe collected in June you would take the 61 we know he has already got away from the grand total of 94 (94-61=33) this means in June he collects 33 stamps. Hope this helps :)

8 0
2 years ago
A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.
Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

p(m) = 0.52 (which corresponds to 52%)

While the probability that the birth is a female can be written as

p(f) = 0.48 (which corresponds to 48%)

Here we want to calculate the probability that over  2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male  does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

p(mm)=p(m)\cdot p(m)

And substituting, we find

p(mm)=0.52\cdot 0.52 = 0.27

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

p(ff)

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

p(ff)=p(f)\cdot p(f)

And substituting

p(f)=0.48

We find:

p(ff)=0.48\cdot 0.48=0.23

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely p(mf)

- The probability that 1st child is a female and 2nd child is a male, namely p(fm)

So, this probability is

p(mf Ufm)=p(mf)+p(fm)

We have:

p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25

p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25

Therefore, this probability is

p(mfUfm)=0.25+0.25=0.50

So, 50%.

Learn more about probabilities:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

5 0
3 years ago
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