Question

Write the equation of a hyperbola with vertices at (-4, 0) and (4, 0) and co-vertices (0, 5) and (0, -5).

Answer 1

Answer:

The answer to your question is  $\frac{x^{2}}{16} - \frac{y^{2} }{25} = 1$

Step-by-step explanation:

Data

(-4, 0)   (4, 0)

(0, 5)    (0, -5)

Plot the point to determine if it is a horizontal or vertical hyperbola

It is a horizontal hyperbola because the vertices are in a horizontal line. The center is (0, 0).

a = 4

b = 5

Formula

              $\frac{x^{2} }{a^{2}} - \frac{y^{2}}{b^{2}} = 1$

Substitution

             $\frac{x^{2}}{4^{2}} - \frac{y^{2}}{5^{2}} = 1$

Equation

            $\frac{x^{2}}{16} - \frac{y^{2}}{25} = 1$