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monitta
3 years ago
7

An urn contains 6 red balls and 3 blue balls. One ball is selected at random and is replaced by a ball of the other color. A sec

ond ball is then chosen. What is the conditional probability that the first ball selected is red, given that the second ball was red?
Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

0.5882 or 58.82%

Step-by-step explanation:

The probability that both balls were red (A) is:

P(A)=\frac{6}{9}*\frac{5}{9}=0.3704

The probability that the first ball was blue and the second ball was red (B) is:

P(B) = \frac{3}{9}*\frac{7}{9}=0.2593

The conditional probability that the first ball selected is red, given that the second ball was red is:

P = \frac{P(A)}{P(A)+P(B)}=\frac{0.3704}{0.3704+0.2593} =0.5882

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