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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

1 answer:

RUDIKE [14]3 years ago

4 0

Jackie wants to keep her total work time <em>under </em>20 hours, so we can set up a rough inequality right away:

(work time in hours) < 20

Now, it's going to take here 1/2 = 0.5 hours to finish each necklace, an 1 hour to finish each bracelet, so if she's making x necklaces, it'll take her 0.5x hours to make all of them, and if she's making y bracelets, it'll take her 1y = y hours to finish those. Putting the two together, it'll take her 0.5x + y hours altogether to make the necklaces and bracelets. Putting that together with our first inequality, we get the final inequality

0.5x + y < 20

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2 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

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Step-by-step explanation:

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2 years ago