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3 years ago

If 168 choclate chips weigh 5 1/4 how many chocalte chips are in an oz

Mathematics

1 answer:

Alenkasestr [34]3 years ago

3 0

There would be 32 Chocolate chips.

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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3 years ago

Which is the constant term in the equation given in standard from 5x+3y=15

Alisiya [41]

Answer:

Step-by-step explanation:

The constant is the term without the variable

5x+3y=15

15 is the constant

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3 years ago

What is the answers

postnew [5]

2,4,6,8,10,0,0,0,0,0,1,4,9,16,25,1,2,3,4,5

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Answer:

3hours and 30 minutes moving and 2 and a half hours stationary

Step-by-step explanation:

1 hour + 30 minutes + 1 hour + 30 minutes + 30 minutes for moving

1 hour + 1 hour + 30 minutes for stationary.

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3 years ago

I never see to pretty best friend one of them got to be ugly. if you know you know

Elina [12.6K]

Answer:lol

Step-by-step explanation:

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