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WINSTONCH [101]
3 years ago
8

In the coordinate plane, what is the length of the line segment that connects points at (5, 4) and (−3, −1) ? Enter your answer

in the box. Round to the nearest hundredth. units
Mathematics
1 answer:
stiks02 [169]3 years ago
3 0
The distance between two points knowing theirs coordinates:

AB =√[(x₂-x₁)² +(y₂-y₁)²]; ===>A(5,-4) & B(-3,-1) Given
                                                A(x₁,y₁) & B(x₂,y₂)

AB =√[(-3-5))²+(-1-(-4)²] =√(73) = 8.381 ≈ 5.44 units
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Find the equation of a line parallel to y=-10x-5 passing through the coordinate (-3,5)
Allushta [10]
With a given parallel line and a given point on the line
we can use the point-line method:  y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.

Here
m=-10, k=-5, (x0,y0)=(-3,5)

=> the required line L is given by:
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on simplification
L: y=-10x-30+5
L: y=-10x-25
4 0
3 years ago
Three vectors A, B, C in three-dimensional space satisfy the following properties
wlad13 [49]

Answer:

\frac{7}{8}\pi

Step-by-step explanation:

observe

||a–b+c|| = ||a+b+c||

(a-b+c)² = (a+b+c)²

(a+b+c)² – (a-b+c)² = 0

((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0

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(a+c)b = 0

a•b + c•b = 0

||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0

\cos(\theta)=-\frac{||a||\times ||b|| \times \cos(\frac{\pi}{8})}{||c||\times ||b||}=-\cos(\frac{\pi}{8})\\ \theta=\frac{7}{8}\pi

3 0
3 years ago
A rectangle has a width of 46 centimeters and a perimeter of 204 centimeters. What is the rectangle’s length?
Vanyuwa [196]

Answer:

Length = 56

Step-by-step explanation:

Perimeter = Length + Length + Width + Width

Perimeter = 2L + 2W

2L + 2W = 204

2L + 2(46) = 204

2L + 92 = 204

Subtract 92 from both sides

2L = 112

Divide both sides by 2

L = 56

Length = 56

7 0
3 years ago
Can someone please help me with this problem
Nadusha1986 [10]
X= 2/3

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X(6x-4) / x(x-6)

6x-4/x-5 = 0

6x-4= 0

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5 0
3 years ago
Please help asap i really need it.
pishuonlain [190]
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= 6/3
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