Answer:
81144
Step-by-step explanation:
Answer:
D.540
if im wrong sorry
Step-by-step explanation:
Mean number of errors in each page = 0.01
Mean number of errors in 100 pages = 0.01*100=1
It is possible to use the cumulative distribution function (CMF), but the math is a little more complex, involving the gamma-function. Tables and software are available for that purpose.
Thus it is easier to evaluate with a calculator for the individual cases of k=0,1,2 and 3.
The Poisson distribution has a PMF (probability mass function)
![](https://tex.z-dn.net/?f=)
![P(k):=\frac{\lambda^ke^{-\lambda}}{k!}](https://tex.z-dn.net/?f=P%28k%29%3A%3D%5Cfrac%7B%5Clambda%5Eke%5E%7B-%5Clambda%7D%7D%7Bk%21%7D)
with λ = 1
=>
![P(0):=\frac{1^0e^{-1}}{0!}=0.3678794](https://tex.z-dn.net/?f=P%280%29%3A%3D%5Cfrac%7B1%5E0e%5E%7B-1%7D%7D%7B0%21%7D%3D0.3678794)
![P(1):=\frac{1^1e^{-1}}{1!}=0.3678794](https://tex.z-dn.net/?f=P%281%29%3A%3D%5Cfrac%7B1%5E1e%5E%7B-1%7D%7D%7B1%21%7D%3D0.3678794)
![P(2):=\frac{1^2e^{-1}}{2!}=0.1839397](https://tex.z-dn.net/?f=P%282%29%3A%3D%5Cfrac%7B1%5E2e%5E%7B-1%7D%7D%7B2%21%7D%3D0.1839397)
![P(3):=\frac{1^3e^{-1}}{3!}=0.0613132](https://tex.z-dn.net/?f=P%283%29%3A%3D%5Cfrac%7B1%5E3e%5E%7B-1%7D%7D%7B3%21%7D%3D0.0613132)
=>
![P(k](https://tex.z-dn.net/?f=P%28k%3C%3D3%29%3DP%280%29%2BP%281%29%2BP%282%29%2BP%283%29%3D0.9810118)
or
P(k<=3)=
0.9810 (to four decimal places)
Wow that’s a lot of money for getting a B,if I don’t get 95 percent A in any of my classes I won’t be able to walk after my mom finds out.