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Bad White [126]
3 years ago
5

WILL MARK YOU BRAINLIEST!!

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

B. B and C

Step-by-step explanation:

The compass point is a point or points that point towards north, south, east, west, North-East, South-East, South-West and North-West. So point B and C are compass points. Hope this helps! :3

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How many times does 5 go in to 47
Feliz [49]
47/5=9.40
9*5=45
47/5= 9 2/5
6 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Fine the value of X
makvit [3.9K]

Answer:

30

Step-by-step explanation:

60/40=3/2

105/40+x = 3/2

105/70=3/2

x=70-40 = 30

8 0
4 years ago
Read 2 more answers
I thought of a number, added 26 to it, and then divided the result by 20. What is my number?
inessss [21]

Answer:

12?

Step-by-step explanation:

4 0
3 years ago
Initial Knowledge Check
Cloud [144]

Answer:

I believe it would be five dollars since if you divide the price with the percentage yknow

5 0
3 years ago
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