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Goshia [24]
4 years ago
10

Does anyone know how to solve this?

Mathematics
1 answer:
Charra [1.4K]4 years ago
5 0

Answer:

\frac{\sqrt{2}}{2}

Step-by-step explanation:

This almost looks like the left hand side of the following identity:

\sin(A)\cos(B)-\sin(B)\cos(A)=\sin(A-B) .

Here are similar identities in the same category as the above:

\sin(A)\cos(B)+\sin(B)\cos(A)=\sin(A+B)

\cos(A)\cos(B)-\sin(A)\sin(B)=\cos(A+B)

\cos(A)\cos(B)+\sin(A)\sin(B)=\cos(A-B)

Things to notice: 90-76=14. and 90-59=31.

This means we will possibly want to use the following co-function identities:

\cos(90-A)=\sin(A)

\sin(90-A)=\cos(A)

So let's begin:

\sin(76)\cos(31)-\sin(14)\cos(59)

Applying the co-function identities:

\cos(14)\cos(31)-\sin(14)\sin(31)

Applying one of the difference identities above with cosine:

\cos(31+14)

\cos(45)

45 is a special angle so \cos(45) is something you find off most unit circles in any trigonometry class.

\cos(45)=\frac{\sqrt{2}}{2}

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Answer:

We cannot prove

Step-by-step explanation:

If we want to prove by SSS congruent,  corresponding sides of both triangles should be congruent.

Here, Only 2 angles and side are congruent.

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Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou
storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

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I = ?  

We have the following compound interest formula

P' = P*(1+\dfrac{r}{n})^{nt}

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So the new principal P' after 5 years is approximately $42,706.66.  

Subtracting the original principal from this amount gives the amount of interest received:

P' - P = I

42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark

________________________

I Hope this helps, greetings ... Dexteright02! =)

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Answer:

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Step-by-step explanation:

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Solve this problem by performing the operation,

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