4 years ago

Can some tell me the answer for 6a and b please!

Mathematics

1 answer:

Allushta [10]4 years ago

3 0

6a.
output y differences
0
3
3
3
6
3
9
3
12
3
15

You might be interested in

Determine if the following relation is a function or not

Darya [45]

1 is not. 2 is. 3 is not. 4 is. 5 is. 6 is. 7 is not. 8 is.

7 0

3 years ago

Use the distributive property to find the product. Show your work (3x^2 + 4x +8)(x^2 + 3x)

Stells [14]

The answer = 3x^4+13x^3+20x^2+24x

3 0

3 years ago

Tres mineros,A,B,C.con cargas de 40,50 y 90 kg, respectivamente , se disponen a cruzar el rio. Se sabe que el bote solo puede tr

Veseljchak [2.6K]

10 y porque estas copiando

6 0

3 years ago

Determine whether the three given points are collinear. (3, 2), (4, 6), (0, 8) True: they are collinear False: they are not coll

FinnZ [79.3K]

Answer:

They are not co-linear.

Step-by-step explanation:

For three point's to be co linear the slopes of the lines connecting them should be same

Mathematically we can write for $(x_{1},y_{1}),(x_{2},y_{2}),(x_{3},y_{3})$

to be co-linear we should have

$\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{y_{3}-y_{1}}{x_{3}-x_{1}}$

Applying the given values we obtain

$\frac{y_{3}-y_{2}}{x_{3}-x_{2}}=\frac{8-6}{0-4}=-1/2\\\\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{6-2}{4-3}=3\\\\\frac{y_{3}-y_{1}}{x_{3}-x_{1}}=\frac{8-2}{0-3}=-2$

As we can see the values are not equal thus the points are not co-linear.

6 0

3 years ago

A female parrot that weighs 13.44 ounces has a chick that

borishaifa [10]

24 divide the numbers

5 0

3 years ago

Read 2 more answers