Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cosθ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Angle θ = 45°
Adjacent Leg = 25
Hypotenuse = <em>x</em>
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in variables [cosine]:

- [Multiplication Property of Equality] Multiply 25 on both sides:

- Rewrite:

- Evaluate:

12 out of 40 to a percentage:-
(12/40)×100
= 30%
<h2>
Hope it helps..</h2>
Step-by-step explanation:
M/6-7=2/3
M/6=2/3+7
M=23/3×6
M=23×2=46
Answer:
59049 each term is the last multiplied by -3.
Answer:
It will take Sarah 2 1/2 hours to mow 10 lawns
It will take Sarah 1 2/3 hours to clean 10 pools
Step-by-step explanation:
During the summer holidays, Sarah earns pocket money by mowing the lawn. She can mow 6 lawns in 1 1/2 hour and clean a pool in one-sixth of an hour. How long does Sarah take to clean 10 pools and 10 lawns?
Number of lawns : Time to mow lawns = 6 : 1 1/2
= 6 : 3/2
Number of lawns : Time to mow lawns = 10 : x
6 : 3/2 = 10 : x
6 ÷ 3/2 = 10/x
6 * 2/3 = 10/x
12/3 = 10/x
Cross product
12 * x = 3 * 10
12x = 30
x = 30/12
x = 2 6/12
x = 2 1/2 hours
It will take Sarah 2 1/2 hours to mow 10 lawns
Number of pools cleaned : time taken = 1 : 1/6
Number of pools cleaned : time taken = 10 : x
1 : 1/6 = 10 : x
1 ÷ 1/6 = 10/x
1 * 6/1 = 10/x
6 = 10/x
Cross product
6 * x = 10
6x = 10
x = 10/6
x = 1 4/6
x = 1 2/3 hours
It will take Sarah 1 2/3 hours to clean 10 pools