PLEASE HELP ME SOLVE THIS!

Write an equation for a circle with a diameter that has end points at (-4,-1) and (-8,-9) round to the nearest tenth if necessar

Mazyrski [523]

1) distance formula; d = √(x2-x1)² +(y2-y1)² . d= √(-4-8)² +(-3-7)² = > d= 2√61

diameter = 2*radius => 2√61 =2r => r =√61 => r² =61

midpoint of the diameter is:

Xm= -4-8 /2 -6 => -6
Ym = -1-9 /2 -5 => -5 center of the cirlce is at (-6,-5)

general equation of a circle: (x-x1)² +(y-y1)² =r² with (x1,y1) being the center of the circle.

equation: (x+6)+(y+5)=61

6 0

3 years ago

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

4 years ago

One month Tammy rented 2 movies and 3 video games for a total of $25. The next month she rented 4 movies and 8 video games for a

mojhsa [17]

Answer:

cost of each video game = $5.50

cost of each movie = $4.25.

Step-by-step explanation:

Let m represent cost per movie

g represents cost per video game.

Create two equations to represent the total cost Tammy rented movie and video games in each month, and solve simultaneously for each variable:

First month:

$2m + 3g = 25$ => equation 1

Second month:

$4m + 8g = 61$ => equation 2

Multiply equation 1 by 4, and multiply equation 2 by 2 to derive:

4 × $2m + 3g = 25$

2 × $4m + 8g = 61$

$8m + 12g = 100$ => equation 3

$8m + 16g = 122$ => equation 4

Subtract equation 4 from equation 3

You'd have:

- 4g = - 22

Divide both sides by -4

g = 5.5

Thus, the cost of each video game = $5.50.

Substitute g = 5.5 in equation 1 and solve for m.

$2m + 3g = 25$

$2m + 3(5.5) = 25$

$2m + 16.5 = 25$

Subtract 16.5 from each side

$2m = 25 - 16.5$

$2m = 8.5$

Divide both sides by 2

$m = 4.25$

Thus, cost of each movie = $4.25.

5 0

3 years ago

La distancia en Km. De Santo Domingo a Puerto Plata está dada por la expresión D = 4x³- 10x² -6. ¿Cuál es la distancia aproximad

neonofarm [45]

Answer:

The distance when x = 6km is D = 498 KM

Step-by-step explanation:

Here, given the formula for the distance, we want to find the distance D given the value of x to be 6km

What we do simply here is to substitute the value 6km as x in the equation

The equation is

D = 4x^3 - 10x^2 -6

Substituting x = 6, we have

D = 4(6^3) -10(6^2) -6

D = 864-360-6

D = 498 km

8 0

3 years ago

Factor 15x+35 using the GCF

laila [671]

The answer is 5(3x+7). 5 is the GCF

4 0

3 years ago