Question

The length of a rectangle is 6 ft longer than twice the width. If the perimeter is 66 ​ft, find the length and width of the rectangle.

Answer 1

Length (L): 2w + 6

width (w): w

Perimeter (P) = 2L + 2w

                66 = 2(2w + 6) + 2(w)

                66 = 4w + 12 + 2w

                 66 = 6w + 12

                  48 = 6w

                   8 = w

Length (L): 2w + 6   = 2(8) + 6   = 16 + 6   = 22

Answer: width = 8 ft, length = 22 ft