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nata0808 [166]
3 years ago
8

PLEASE HELP 21 points!!

Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:

14. 36

15. 12.5

16. 2.5

17. -34,359,738,368

Step-by-step explanation:

14.

F(2) = 6^2

= 36

15.

G(-2) = 2*.4^-2

= 2*1/.16

= 2/.16 or 1/.08 or 12.5

16.

y = 20*.5^3

= 20*.125

= 2.5

17.

H(w) = -0.5*4^18

= -34,359,738,368

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Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

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Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

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