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3 years ago

12

Answer this question please

1 answer:

NARA [144]3 years ago

5 0

Answer:

The answer is 2

Step-by-step explanation:

formula: y2 - y1 / x2 -x1

substitute: 3 - 5 / 3 - 1 = 2 / 1 = 2

Pls make as brainliest))))

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In the flower bed are 10 daisies and 4 sunflowers, compare the flower using ratio.

astraxan [27]

5:2 in simplest form. 10:4 in normal

3 0

3 years ago

Can a triangle can have sides with lengths 2.7, 3.5, and 9.8.

blagie [28]

Answer: No

Step-by-step explanation:

2.7 + 3.5 is not greater than 9.8.

8 0

3 years ago

Read 2 more answers

What is the distance between the following coordinates? Show work.

miss Akunina [59]

Answer:

$\huge{ \boxed{ \bold{ \tt{2 \sqrt{26}}} \: \: \text{units} } }$

<h3>♁ Question :</h3>

Find the distance between ( 5 , -6 ) and ( 3 ,4 ).

<h3>♁ Step by step explanation:</h3>

Let the points be A and B. Now,

Let, A ( 5 , -6 ) ⇢ ( x₁ , y₁ )
Let, B ( 3 , 4 ) ⇢ ( x₂ , y₂ )

Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

$\boxed{ \underline{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}}$

Substitute the actual value of the points into the distance formula and then simplify.

$\dashrightarrow{ \sf{ \sqrt{ {(3 - 5)}^{2} + {(4 - ( - 6))}^{2} } }}$

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

$\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 - ( - 6))}^{2} } }}$

Remember : ( - ) × ( - ) = ( + )

$\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 + 6)}^{2} } }}$

Add the numbers : 4 and 6

$\longrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(10)}^{2} } }}$

Evaluate the power

$\longrightarrow{ \sf{ \sqrt{4 + 100}}}$

Add the numbers : 4 and 100

$\dashrightarrow{ \sf{ \sqrt{104}}}$

$\dashrightarrow{ \boxed{ \sf{2 \sqrt{26} }}}$ units

Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is $\sf{2 \sqrt{26}}$ units .

And we're done!

Hope I helped!

Have a wonderful time ! シ

~TheAnimeGirl

5 0

3 years ago

A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its

VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate ( $\dot V$ ), measured in liters per hour, is directly proportional to draining time ( $t$ ), measured in hours. That is:

$\dot V \propto \frac{1}{t}$

$\dot V = \frac{k}{t}$ (Eq. 1)

Where $k$ is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

$\dot V_{s}+\dot V_{l} = \frac{k}{2}$ (Eq. 2)

$\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}$

(ii) <em>Only the small drain is opened</em>

$\dot V_{s} = \frac{k}{t_{l}+3}$ (Eq. 3)

$\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}$

(iii) <em>Only the big drain is opened</em>

$\dot V_{l} = \frac{k}{t_{l}}$ (Eq. 4)

$\frac{\dot V_{l}}{k} = \frac{1}{t_{l}}$

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

$\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}$

$\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}$

$2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}$

$t_{l}^{2}-t_{l}-3 = 0$ (Eq. 5)

Whose roots are determined by the Quadratic Formula:

$t_{l,1}\approx 2.303\,h$ and $t_{l,2} \approx -1.302\,h$

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

$t_{s} = 2.303\,h+3\,h$

$t_{s} = 5.303\,h$

The draining time when only the small drain is opened is 5.303 hours.

7 0

3 years ago

Identify all the real solutions of the graph below

Marizza181 [45]

I don’t think it has any real solutions

6 0

3 years ago