Please help me with these questions down below i would really appreciate it!

Mazyrski [523]

Answer:

Slope: $\frac{3}{5}$

Y-Intercept: $(0,-5)$

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is $y=mx+b$ . In this case, our equation is already in this form. $m$ is what your slope is. In this case, our

2. To find the y-intercept we look at value $b$ that is in $y=mx+b$ . In this case, $b$ is $-5$ . So, our ordered pair is $(0,-5)$ .

4 0

2 years ago

Read 2 more answers

Help me please Solve for r <br> d=rt

Vika [28.1K]

Watch closely. I'll try to go slow.
Stop me if I go too fast, or if I do anything that you don't understand.

Ready ?

You said d = r t

Divide each side by ' t ' : d / t = r

5 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$