Answer:
numbers = '14 36 31 -2 11 -6'
nums = numbers.split(' ')
for i in range(0, len(nums)):
nums[i] = int(nums[i])
print(nums)
Answer:
<em><u>The</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>C</u></em><em><u> </u></em><em><u>no</u></em>
Explanation:
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>dear</u></em><em><u> </u></em><em><u /></em>
Answer:
The probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is 0.964
If the survey subjects <em>volunteered</em> to respond , then those with the strongest opinions are most likely respond. The survey sample is then not randomly selected, the survey may have a <em>response bias.</em>
Explanation:
Let P(at least one is more careful about personal information when using a public Wi-Fi hotspot) denote the probability that among three randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot, then we have the equation
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot)
- If 67% of Internet users are more careful about personal information when using a public Wi-Fi, then 33% of them are not.
P(none of the selected users is more careful about personal information when using a public Wi-Fi hotspot) =
≈ 0.036
P(at least one is more careful about personal information when using a public Wi-Fi hotspot) = 1 - 0.036 = 0.964
Answer:Computers only understand machine code - they do not understand high-level language code. Any high-level programming language code has to be converted to executable code. Executable code is also known as machine code which is a combination of binary code 0s and 1s.
Explanation:
Answer:
Direct Mapped Cache
Explanation:
Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.
It is considered cheaper compared to the associative method of cache mapping, and it is faster when searching through it. This is because it utilizes a tag field only.
Hence, The method of mapping where each memory location is mapped to exactly one location in the cache is "Direct Mapped Cache"