Find two numbers such that one exceeds the other by 11 and their sum is 73.
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We will get the areas of each one of the given triangles:
7) A = 12.69 mm²
8) A = 19.21 in²
9) A = 16.81 yd²
<h3>How to get the area of the given triangles?</h3>
7) First, we have an equilateral triangle, where all the sides measure 5.4mm
For an equilateral triangle of side length S, the area is:
In this case, S = 5.4 mm, replacing we get:
8) Now we have two equal sides and one different. The general area of a triangle of base B and height H is:
A = B*H/2.
In this case, the base measures 3.4 in.
To get the height, let's divide the triangle into two right triangles, such that one cathetus is 3.4in/2 = 1.7 in.
The hypotenuse measures 5.9 in
And the other cathetus is the height of the triangle.
Then, by using the Pythagorean theorem, we see that the height is:
Then the area of this triangle is:
9) Here the base measures 8.2 yds, and the height 4.1 yds, so the area is just:
If you want to learn more about triangles:
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