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Sloan [31]
4 years ago
11

If an integer from 3 through 14 is chosen at random, what is the

Mathematics
1 answer:
shutvik [7]4 years ago
3 0

Answer:\frac{7}{12}

Step-by-step explanation:

Given

There are integer between 3 and 14 available to be chosen (total 12 integers)

Prime integers among them

3,5,7,11,13 i.e. total of 5 prime integers

So the probability that the number chosen is not Prime

=1-P\text{(no is prime)}

=1-\frac{5}{12}

=\frac{12-5}{12}

=\frac{7}{12}

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A large bakery buys flour in 20-pound bags. The bakery uses an average of 1050 bags a year. Preparing an order and receiving a s
emmasim [6.3K]

Given the following:

  • Demand = 1050
  • Ordering cost = 15
  • Holding cost = 55

The economic order quantity is 24.

<h3>What is the economic order Quantity?</h3>

Eoq = √2 * demand * ordering cost / holding cost)

= √(2 * 1050 * 15 / 55)

EOQ = 24

<h3>What is the average number of bags on-hand?</h3>

The  Average inventory = EOQ / 2

= 24 / 2

= 12

<h3>How many orders per year will there be?</h3>

Expected number of orders = demand / EOQ

= 1050 / 24

= 44

<h3>What is the total cost of ordering and carrying flour?</h3>

Annual holding cost (AHC) = (EOQ / 2) * Holding cost

= (24 / 2) * 55

= 660

Annual ordering cost (AOC) = (demand / EOQ) * ordering cost

= (1050 / 24) * 15

= 656

Thus,

Total cost of managing = AHC + AOC

= 660 + 656

TCM = 1,316

<h3>If holding costs were to increase by $5 per year, how much would the minimum total annual cost?</h3>

5. For holding cost of 60

EOQ= √(2 * demand * ordering cost / holding cost)

= √(2 * 1050 * 15 / 60)

= 23

Annual holding cost = (EOQ / 2) * holding cost

this gives us

= (23 / 2) * 60

= 690

Annual ordering cost = (demand / EOQ) * ordering cost

= (1050 / 23) * 15

= 685

Total cost of managing = AHC+ AOC

= 690 + 685

= 1375

Change in total annual cost = new - old

= 1375 - 1316

= 59

Learn more about Economic order quantity:
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8 0
2 years ago
Drew purchased a 4K Blu-ray for $18.00 and sold it to a customer on EBay for 50% more than the purchase price . The customer was
Setler [38]

Answer: $24.84

Step-by-step explanation: So if the seller sold the Blu-ray for 50% more than the original purchase price, it will equal to $27 from $18.00 - a $9.00 difference. An 8% sales tax was then charged on top of the $27.00 purchase that would total to $2.16 deduction.

$27.00 - 2.16 = <u>$24.84</u> for the total cost of the Blu-ray.  

3 0
3 years ago
The distance a car has traveled can be represented by the equation d = 1.4m, where d represents the distance in miles and m repr
ValentinkaMS [17]

Answer:

It is the velocity of the car, the speed.

5 0
3 years ago
Can someone help me pls
algol [13]

Answer:

from least to greatest 112 121 124 137 147 156 173 189

Step-by-step explanation:

if you subtract each number from a number that is greater than all the numbers for example 200 then what ever has the most left will be greatest and least will be least for example 121 - 200 is negative 79 and 189 - 200 is negative 11 negative 11 is higher so its a greater number there is also easier ways to do this but this is just extra

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3 years ago
Read 2 more answers
Show that if matrices A and B have the same RREF, then A can be turned into B by a finite sequence of elementary row operations.
Anettt [7]

Answer:

The answer is below

Step-by-step explanation:

A matrix is in row echelon form if it satisfies the following three conditions:

(i). All non-zero rows are above any zero rows.

(ii). Each leading entry in a row is in a column to the right of the leading entry of the row above it.

(iii). All the entries in a column below a leading entry are zeros.

The following operations on a matrix are called elementary row-operations:

1. Interchanging the ith and the jth rows, expressed as ri <--> rj.

2. Replacing the ith row by a multiple of itself expressed as ri --> krj, where k is a non-zero scalar.

3. Replacing the jth row by the sum of itself and a non-zero multiple of the ith row, expressed as rj --> rj + kr.

It may be observed that all the 3 elementary row-operations are reversible. Thus. ri <--> rj can be reversed by ri <--> rj,  ri --> kri can be reversed by ri -->(l/k)*ri, (here ri indicates the new ith row) and  rj --> rj + kr can be reversed by rj --> rj - krj.

Now, since both the matrices A and B are reduced to the same RREF C (say), hence reversing the elementary operations used to reduce B to C, we get B from C. Thus, A can first be converted to C and then to B.

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