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3 years ago

What is the simply interest. principal $ 300, rate 6.8 % time half a year 6 months

2 answers:

7 0

The formula for simple interest for months is I=P * (r / m) * n. Where P is the principle and r is rate and m is the year or 12 months and n equals how many months.

I=300 * (0.068 / 12) * 6 = 10.2

So the interest would be $10.2

Dmitriy789 [7]3 years ago

6 0

I=PRT
I=interst
P=principal
R=rate
T=time in years

I=?
P=300
R=0.068
T=0.5

I=(300)(0.068)(0.5)
I=10.2

interest is $10.2

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Which is larger 1:40 or 1:60

agasfer [191]

1:40.

1:40 is equal to 1/40, while 1:60 is equal to 1/60.

1/40 is the bigger fraction, so 1:40 is the correct answer.

3 0

3 years ago

Pleaseee helpppp I really need it now please

lozanna [386]

Answer:

c = 60

Step-by-step explanation:

A triangle = 180 degrees

180-(15+105)=c

c=60

5 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

3 years ago

2. On a number line, G = 8 and H = –3. If H is the midpoint of GI , find the coordinate of I.

MissTica

Answer:

-14

Step-by-step explanation:

the coordinate of I :

H = 8+I /2

-3 = 8+I /2

8+I = 2×(-3)

8+ I = -6

I = -6-8

I = -14

8 0

3 years ago

A math class has 3 girls and 7 boys in the 7th grade and 5 girls and 5 boys in the 8th grade the teacher randomly selects a seve

Minchanka [31]

In the 7th and 8th grade combined, there 3+5 girls = 8 girls, and 7+5 boys = 12 boys. If there are only boys and girls, then there are 12+8=20 students in all.

The fraction of girls out of the total is P = 8/20 = 2/5.

8 0

3 years ago