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4 years ago

5

Please answer please correct answer

1 answer:

netineya [11]4 years ago

7 0

Answer:

∆GFI AND ∆JIK

∆GFI AND ∆JIK are corresponding angles

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Tyler picks 3/3 dozen apples. Olivia picks 5/6 dozen apples. Samantha picks 2/3 dozen apples. Who picks the least number of appl

Kitty [74]

For this case we have the following apple picking options, in dozens:

<em>Tyler:</em>

$\frac {3} {3} = 1$

Tyler picked up a dozen.

<em>Olivia:</em>

$\frac {5} {6} = 0.833$

Olivia collected 0.833 dozen apples.

<em>Samantha:</em>

$\frac {2} {3} = 0.667$

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

Samantha

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3 years ago

Which of the bbb-values satisfy the following inequality?

Jet001 [13]

Answer:

22

Step-by-step explanation:

7 0

3 years ago

What is the 45th multiple of 80

meriva

3600 if you multiply 40 to 80<span />

5 0

3 years ago

What is the solution to the system of equations?

Burka [1]

Answer:

(10, -20).

Step-by-step explanation:

y= -5x + 30

x = 10

Substitute x = 10 in the first equation:

y = -5*10 + 30

y = -50 + 30

y = -20.

So the solution is (10, -20).

4 0

3 years ago

Read 2 more answers

The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is

Natalka [10]

Answer:

The standard form of the equation for this line can be:

l: 2x + 5y = -15.

Step-by-step explanation:

Start by finding the slope of this line.

For a line that goes through the two points $(x_0, y_0)$ and $(x_1, y_1)$ ,

$\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}$ .

For this line,

$\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}$ .

Find the slope-point form of this line's equation using

$\displaystyle \text{Slope} = -\frac{2}{5}$ , and
The point $(-5, -1)$ (using the point $(10, -7)$ should also work.)

The slope-point form of the equation of a line

with slope $m$ and
point $(x_{0}, y_{0})$

should be $l:\; y - y_{0} = m(x - x_0)$ .

For this line,

$\displaystyle m = -\frac{2}{5}$ , and
$x_0 = -5$ , and
$y_0 = -1$ .

The equation in slope-point form will be

$\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5))$ .

The standard form of the equation of a line in a cartesian plane is

$l: \; ax + by = c$

where

$a$ , $b$ , and $c$ are integers. $a \ge 0$ .

Multiply both sides of the slope-point form equation of this line by $5$ :

$l:\; 5 y + 5 = -2x -10$ .

Add $(2x-5)$ to both sides of the equation:

$l: \; 2x + 5y = -15$ .

Therefore, the equation of this line in standard form is $l: \; 2x + 5y = -15$ .

7 0

3 years ago