<span>50 = 5 × 10 + 0 × 1 (5
in the tens place, and 0 in units). </span><span>
<span>We can write each place as a power of ten: </span>
<span>50 = 5 × 10^1 + 0 × 10^0 </span>
<span>Similarly for hexadecimal and binary, but then
using powers of 16 and 2 respectively. </span>
<span>We need to find the digits of the hexadecimal
form. Or in other words, we need to find a and b: </span>
<span>50 = a × 16 + b × 1 </span>
<span>Simply divide 50 by 16 will get you a with some
remainder, which is a multiple in units, and thus b: </span>
<span>50 / 16 = 3 (=a), remainder 2. </span>
<span>[2 / 1 = 2 (=b), remainder 0] </span>
<span>Thus 50 in hexadecimal is "32". </span>
<span>For binary, we need to do the division a couple of
times more to find all digits. </span>
<span>50 = a × 32 + b × 16 + c × 8 + d × 4 + e × 2 + f ×
1 </span>
<span>50 / 32 = 1 (=a), remainder 18 </span>
<span>18 / 16 = 1 (=b), remainder 2 </span>
<span>2 / 8 = 0 (=c), remainder 2 </span>
<span>2 / 4 = 0 (=d), remainder 2 </span>
<span>2 / 2 = 1 (=e), remainder 0 </span>
<span>[0 / 1 = 0 (=f), remainder 0] </span>
<span>We find that 50 in binary is "110010".</span></span>
<span>(5p^4)^3 · (2p^3)^4
5^3p^12 * 2^4p^12
125p^12 * 16 p^12(in multiplication add the powers
2000 p^12+12
answer= 2000 p^24</span>
To get a single h, all you have to do is divide everything by 4
so h =
Y-2=-3(x-y) or y=Mx+b or y=-3x+23 either way it works
There 54,550 more smaller paper clips than larger paper clips.