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3 years ago

Help please..... 11 pointsssss

Mathematics

2 answers:

julsineya [31]3 years ago

8 0

X= -213/10 , look at the steps in the picture

kozerog [31]3 years ago

4 0

Multiply both sides by 2.4

5.7+x=-15.6

next subtract 5.7

x=-21.3

I'm pretty sure I did that right

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A water sprinkler sends water out in a circular pattern. How large is the watered area if the radius of the watering pattern is2

Mamont248 [21]

Answer:

Step-by-step explanation:

Simply put, it is similar to finding the area of a circle.

Therefore, a=pi*r^2

a=pi*23^2

a=529pi

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2 years ago

The ratio of black bags to blue bags is 5to 3 if there are a total of 10 black bags ,then how many blue bags are there

LuckyWell [14K]

Answer:

Step-by-step explanation:

We can think of the 10 black bags as 2 sets of 5-black bags (10 divided into groups of 5; 10 / 5 ; is 2 groups/sets). So, we would also have two sets of 3 (3 x 2 = 6), or 6 bags.

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2 years ago

Which two theorems would justify that m∠4 = m∠6, given that m∠5 = m∠6 in the diagram below?

My name is Ann [436]

Answer: D) vertical angles theorem, alternate interior angles theorem

Angle 5 = Angle 6 by the alternate interior angles theorem

Angle 5 = angle 4 by the vertical angles theorem

By the transitive property, we can then say angle 4 = angle 6. These angles are also corresponding angles.

We won't use the angle addition theorem or the right angles theorem.

4 0

3 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Pls answer the question important

Sladkaya [172]

Step-by-step explanation:

no they are not parallel

4 0

3 years ago

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