Question

What is the solution to the linear equation?

Answer 1

QUESTION 1

We want to solve the linear equation,

–12 + 3b – 1 = –5 – b

Group similar terms:

3b+b=-5+1+12

Combine similar terms,

4b=8

Divide both sides by 4

b=2.

QUESTION 2

We want to find the equation of the given line that passes through

(-3,2) and (2,-1)

The slope of this line is

$m = \frac{ - 1 - 2}{2 - - 3} = - \frac{3}{5}$

The equation is given by the formula:

$y-y_1=m(x-x_1).$

We plug in the known values to obtain;

$y + 1= - \frac{3}{5} (x- 2)$

$y + 1= - \frac{3}{5} (x - 2)$

$5y + 5 = - 3x + 6$

$3x + 5y = 1$