It helps immensely if you know your times tables.
a) 36 = 6*6 = 2*3*2*3 = 2^2*3^2
b) 45 = 5*9 = 5*3*3 = 3^2*5
c) 2 is not a common factor; 3^2 is a common factor; 5 is not a common factor. The greatest common factor is 3^2 = 9.
d) The least common multiple can be found a couple of ways.
.. 1) the product of the distinct factors to their highest powers
.. .. .. 2^2 * 3^2 * 5 = 180
.. 2) the product of the numbers divided by their greatest common factor.
.. .. .. 36 * 45 / 9 = 180
4√5
According to Brainly I need to have at least 20 characters before being able to 'Add My Answer'.
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
10
Step-by-step explanation:
z−2(x+5)=
Use the distributive property to multiply −2 by x+5.
z−2x−10
Step-by-step explanation:
using trig, tangent is equal to opposite over adjacent.
in this case, the angle is 45, opposite is 7, and adjacent is a.
thus tan 45° = 7/a
solve for a to get a = 7/tan 45° = 4.32