Solve the equation -3=7+z/2

2 answers:

7 0

<span>-3=7+z/2
Subtract 7 from both sides
-10=z/2
Multipy 2 on both sides so that the only thing remaining on the right side is the variable z.
Final Answer: -20= z</span>

kolezko [41]3 years ago

5 0

Are you suppose to solve the equation to find z if so.. the answer would be
z = -20
Solve for z by simplifying both sides of the equation, then isolating the variable.

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Suppose cos(a)=4/5. use the trig identity sin^2(a)+cos^2(a)=1 to find sin(a) in quadrant IV.

natima [27]

Answer:

sin a = -3/5

Step-by-step explanation:

sin^2(a)+cos^2(a)=1

sin^2(a)+ (4/5)^2 = 1

sin^2(a) = 1 - 16/25 = 9/25

sin a = 3/5 ( in Quadrant 1)

In quadrat IV the sine is negative

so sin a = -3/5

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2 years ago

What is the solution for the equation startfraction 5 over 3 b cubed minus 2 b squared minus 5 endfraction = startfraction 2 ove

kaheart [24]

An equation is formed of two equal expressions. The solution of the equation is 4.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The solution of the equation can be written as,

$\dfrac{5}{3b^3-2b^2-5} = \dfrac{2}{b^3-2}\\\\5(b^3-2) = 2(3b^3-2b^2-5)\\\\5b^3-10=6b^3-4b^2-10\\\\5b^3-10-6b^3+4b^2+10=0\\\\-b^3+4b^2=0\\\\b^2(-b+4)=0\\\\-b+4=0\\\\-b=-4\\\\b=4$