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tresset_1 [31]
3 years ago
6

Solve by square roots 4x^2+11= 59

Mathematics
2 answers:
AnnyKZ [126]3 years ago
6 0

Subtract 11 from each side

4x^2+11-11= 59-11

4x^2 = 48

Divide by 4

4/4x^2 = 48/4

x^2 = 12

Take the square root of each side

sqrt(x^2) = sqrt(12)

x = ±sqrt(4 x 3)

baherus [9]3 years ago
3 0

Answer:

x= ±2 sqrt(3)

Step-by-step explanation:

4x^2+11= 59

Subtract 11 from each side

4x^2+11-11= 59-11

4x^2 = 48

Divide by 4

4/4x^2 = 48/4

x^2 = 12

Take the square root of each side

sqrt(x^2) = sqrt(12)

x = ±sqrt(4*3)

x= ±2 sqrt(3)

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Mazyrski [523]

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4 years ago
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Answer:

a)

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b)

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Step-by-step explanation:

<u>Recursive And Iterative Rules For Sequences</u>

The recursive rules allow finding terms of a sequence as a function of the previous one. The iterative rules provide a formula to compute the n-th term without the need to compute the previous terms.

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