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4 years ago

Question 12

Mathematics

1 answer:

soldi70 [24.7K]4 years ago

6 0

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The tank for a car holds 17 gallons. The gasoline gauge shows the tank is 3/4 full. How much gas is still in the tank?

Give your answer as a whole number or as a mixed fraction reduced to lowest terms.

Answer:

$Gas \: \:left = 12 \frac{3}{4} \: \:gallons \\\\$

Step-by-step explanation:

The tank for a car holds 17 gallons.

The gasoline gauge of the car shows that the tank is 3/4 full.

We are asked to find the remaining gasoline in the tank.

$Gas \: \:left = \frac{3}{4} \times 17 \\\\Gas \: \:left = \frac{51}{4} \\\\Gas \: \:left = 12 \frac{3}{4} \: \:gallons \\\\$

Therefore, the remaining gas in the tank is $12\frac{3}{4}$ gallons.

Alternatively:

$1 - \frac{3}{4} = \frac{1}{4}$

Amount of gasoline consumed = $\frac{1}{4} \times 17 = \frac{17}{4}$

Amount of gasoline left = total - consumed

Amount of gasoline left = $17 - \frac{17}{4} = 12\frac{3}{4} \:\: gallons$

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Tcecarenko [31]

Answer:

Discontinuity at (-4,-2), zero at (-2,0).

Step-by-step explanation:

We are given that a function

$f(x)=\frac{x^2+6x+8}{x+4}$

We have to find the discontinuity and zero of the given function.

Discontinuity: It is that point where the function is not defined.

It makes the function infinite.

$f(x)=\frac{x^2+4x+2x+8}{x+4}$

$f(x)=\frac{(x+4)(x+2)}{x+4}$

When x=-4 then

$f(-4)=\frac{0}{0}$ It is indeterminate form

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After cancel out x+4 in numerator and denominator then we get

$f(x)=x+2$

Substitute x=-4

$f(-4)=-4+2=-2$

Therefore, the point of discontinuity is (-4,-2).

Zero: The zero of the function is that number when substitute it in the given function then the function becomes zero.

When substitute x=-2

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The function is zero at (-2,0).

Hence, option C is true.

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3 years ago

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There are no solutions to this problem,

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3
x
+
1
=
3
x
Step 1: Subtract 3x from both sides.
3
x
+
1
−
3
x
=
3
x
−
3
x
1
=
0
Step 2: Subtract 1 from both sides.
1
−
1
=
0
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kirza4 [7]

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