I haven't learned antiderivitives yet but I can try to logic it
<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.
we reverse chain rule
3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4
6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3
-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2
2, that is from 2x
so
</span>
<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive
</span>
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4
now reverse drivitive again
3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5
2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4
-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3
2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2
4 and 3/4 turns to (4 and 3/4)x
</span>
<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
</span>
<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30
</span>
</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
Answer:
If you want them at the same exact point then since the theif is 9 steps ahead it
will take 3 seconds
Step-by-step explanation:
Robber:
<em>starts at 9</em>
<em>starts at 9add on 5 and you get 14</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19</em>
<em>starts at 9add on 5 and you get 14add 5 more you get 19and another 5 would give you 24</em>
Police:
<em>is</em><em> </em><em>at</em><em> </em><em>0</em><em> </em><em>meters</em><em> </em>
<em>add</em><em> </em><em>8</em><em> </em><em>any</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>8</em>
<em>add</em><em> </em><em>8</em><em> </em><em>more</em><em> </em><em>and</em><em> </em><em>you</em><em> </em><em>get</em><em> </em><em>1</em><em>6</em>
<em>and</em><em> </em><em>another</em><em> </em><em>8</em><em> </em><em>would</em><em> </em><em>get</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>2</em><em>4</em>
Answer:
Do you mean to round the number 653,500,653,500,653,500? Or do you mean to round the number 653,500? If so, for 653,500, the digit in the thousand's place is 5, so it's already rounded to the nearest thousands place.
Step-by-step explanation:
<span>y-2x=-6 and 5x-y=9
step 1: isolate y in the first equation
y = 2x - 6
step 2: substitute the y value on the 2th equation:
5x-(2x-6)=9
step 3: solve the present equation:
5x - 2x + 6 = 9
3x = 9-6
3x = 3
x = 1
step 4: get the y value by replacing the value of x in </span>y = 2x - 6:
<span>
y = 2*1 - 6
y = 2 - 6
y = -4
S={1, -4}
</span>
Answer:
x = -4 and y = 1
Step-by-step explanation:
hope this helps please like and mark as brainliest
