The ratio of the surface areas of two similar solids is 49:100. What is the ratio of their corresponding side lengths?

Mathematics

2 answers:

irga5000 [103]4 years ago

4 0

Answer:

The answer is option C

$\frac{7}{10}$

Step-by-step explanation:

we know that

The ratio of the surface areas of two similar solids is equal to the scale factor squared and the ratio of their corresponding sides lengths is equal to the scale factor

Let

x------> surface area of the smaller solid

y--------> surface area of the larger solid

z-------> scale factor

$z^{2}=\frac{x}{y}$

substitute the values

$z^{2}=\frac{49}{100}$

$z=\frac{7}{10}$

therefore

The ratio of their corresponding sides lengths is equal to $\frac{7}{10}$

algol134 years ago

3 0

<span>ratio of surface area = 49:100
ratio of corresponding lengths = √49:√100 = 7:10
answer: C

Hope this helps

</span>

You might be interested in

Rectangle A has one side which is 6cm long and the other is (x+2)cm long. Rectangle Y has sides of length (2x+1) and 3cm, If the

gregori [183]

Hello,

Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm

The formula for the perimeter of a rectangle is: P=2(base+height)

Then:

$P_A=2(b+h) \\ P_A=2*[6+(x+2)] \\ P_A=2*(x+8) \\ P_A=2x+16 \\ \\ \\ P_B=2(b+h) \\ P_B=2*[3+(2x+1)] \\ P_B=2*(2x+4) \\ P_B=4x+8
$

But we know that the perimeters are the same, so:

$P_A=P_B \\ 2x+16=4x+8 \\ 8=2x \\ \boxed{x=4} \\ \\ Replacing: \\ \\ Lenght\,\,of\,\,A=(x+2)cm\\ Lenght\,\,of\,\,A=(4+2)cm\\ \boxed{Lenght\,\,of\,\,A=6cm}\\ \\ Lenght\,\,of\,\,B=(2x+1)cm\\ Lenght\,\,of\,\,B=(2*4+1)cm\\ \boxed{Lenght\,\,of\,\,B=9cm}$

With the answer of A, we realize that this figure is actually a square.

4 0

4 years ago

If you make a habit of eating 10 carrot sticks a day you could mathematically describe the relationship between the number of da

yan [13]

10 * days
1m = 30 days
10*30
= 300

5 0

3 years ago

1/2 2/4 4/8 are mixed numbers

Mrac [35]

No they are not because it can be simplified

4 0

2 years ago