All categories

3 years ago

Factor completely 4x^2-8x-60

Mathematics

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

(x+3)(x-5)

Step-by-step explanation:

4x^2 - 8x - 60

x^2- 2x - 15

(x+3)(x-5)

You might be interested in

The smith family bought a new tent for a camping tent

Zepler [3.9K]

The volume of a prism is area of the base times height.
This is a triangular prism. The base is a triangle.
The volume is area of the base times height, and the base is a triangle.
Find the area of the triangle and multiply by the height of the prism.

V = volume of the prism
A = area of the base
H = height of the prism
h = height of the triangle
b = base of the triangle

V = AH

V = (1/2)bhH

V = (1/2) * 9 ft * 7 ft * 15 ft

V = 472.5 ft^3

3 0

3 years ago

Read 2 more answers

The heights of a maple tree and a cherry tree have a ratio of 5:2. If the maple tree grew 20 cm and 20 cm was cut off the top of

elena-14-01-66 [18.8K]

Let x be the heights of a maple tree and y be the height of the cherry tree.
We know:
 $\frac{x}{y} = \frac{5}{2}$
The new ratio is obtained like this:
 $\frac{x+20}{y-20} = \frac{3}{1}$ .
From the above equation we get $x= (y-20)\frac{3}{1} -20$ .
then $\frac{ (y-20)\frac{3}{1} -20}{y} = \frac{5}{2}$
Solving the above equation for y we get: $y=160$
So $x=400$
So the first tree is (400-160=240) more taller than cherry tree.

7 0

3 years ago

Jack is mowing a lawn that has a shed. needs to know area of lawn to mow. dimensions of yard are 5x by 13 x-4 . she'd are 2x by

Elena-2011 [213]

The diagram of the lawn and the shed is shown below.

The area of the lawn needed to be mowed equals to the area of the yard minus the area of the shed

The area of the yard = $(5x)(13x-4) = 65 x^{2} -20x$
The area of the shed = $(2x)(2x+4)=4 x^{2} +8x$

The area of the lawn = $65 x^{2} -20x-(4 x^{2} +8x)$
The area of the lawn = $65 x^{2} -20x-4 x^{2} -8x$
The area of the lawn = $61 x^{2} -28x$

5 0

3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Keith_Richards [23]

Answer:

8.0 seconds to the nearest tenth,

Step-by-step explanation:

h=-16t^2 +vt + c.

-16t^2 + 116t + 101 = 0

t = [ -116 + /- √(116^2 - 4*-16*101) ] / (-32)

t = (-116 +/- √19920) / (-32)

t = -0.79, 8.036 (we ignore the negative root)

The time in flight = 8.036 seconds.

4 0

3 years ago

Two tourists went on a hike at dawn. One went from a to b and another one went from b to a. They met at noon but did not stop an

Alecsey [184]

Dawn was at 6 am. Variables a = distance from a to passing point b = distance from b to passing point c = speed of hiker 1 d = speed of hiker 2 x = number of hours prior to noon when dawn is The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as a = cx = 9d cx = 9d x = 9d/c The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as b = dx = 4c dx = 4c x = 4c/d We now have two expressions for x, set them equal to each other. 9d/c = 4c/d Multiply both sides by d 9d^2/c = 4c Divide both sides by c 9d^2/c^2 = 4 Interesting... Both sides are exact squares. Take the square root of both sides 3d/c = 2 d/c = 2/3 We now know the ratio of the speeds of the two hikers. Let's see what X is now. x = 9d/c = 9*2/3 = 18/3 = 6 x = 4c/d = 4*3/2 = 12/2 = 6 Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am. We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.

8 0

3 years ago