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IRISSAK [1]
3 years ago
5

PLEASE HELP!! At a celtic music festival, the tickets for the main stage cost $45, and tickets for the second stage cost $20.

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
A.) m + s = 325 
     45m + 20s = 12,000

b.) 220 people attended main stage

c.) 105 people attended second stage


How you figure this out:

You can first find the value of (s) by using m + s = 325 and subtracting m from both sides. This leaves you with s = -m + 325 as the value of s. Now substitute that into the equation 45m + 20s = 12,000 and you should have something like this -> 45m + 20 (-m + 325) = 12,000   Now distribute the 20 to both (-m) and (325) which then leaves you with this ->  45m - 20m + 6,500 = 12,000
Next thing you would do is combine like terms which in the case is 45m and -20m. Now combine those term to get -> 25m + 6,500 = 12,000  Now you would subtract 6,500 from both sides and then that would leave you with this  -> 25m = 5,500 Lastly divide 25 into both sides to get your solution for m,  m = 220.  Now that you know the value of (m), substitute it into the equation   M + S = 325 and it would look like this -> 220 + s = 325  now you would subtract 220 from both sides to get your solution for s, s = 105  

I really hope this helps and let me know if you have any questions! :)
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Each girl has 7 backpacks. So 7 * 7 = 49. 

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3 years ago
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What is the value of x in the equation 6 (x + 11) = -300
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Step-by-step explanation:

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Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq
AnnyKZ [126]

Answer:

(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the function

                    f(x) = e^{4x} \sqrt{1+e^{2x} }

Now integrating on both sides, we get

                 \int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx

                               =    \int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx

                         

<u><em>Step(ii):-</em></u>

  Let  1 + e^{2x}  = t

           e^{2x}  = t -1  

          2e^{2x}dx = d t

          e^{2x}dx = \frac{1}{2} d t

                = \int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx

                  = \int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }

                 = \frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }

                = \frac{1}{2} \int\limits {(t^{\frac{1}{2}  } t^{1} +t^{\frac{1}{2} } ) } \, dx

                = \frac{1}{2} \int\limits {(t^{\frac{3}{2}  } +t^{\frac{1}{2} } ) } \, dx

               = \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C

              =  \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C

             = \frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C

            = (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

<u><em>Final answer:-</em></u>

= (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

             

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olga55 [171]

Answer:

178 pages

Step-by-step explanation:

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9 x 12 = 108

11 x 12 = 132

108 x 132 = 14256

8 x 10 = 80

14256/80 = 178 with a little left over

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