Question

Two points are located at (−9,−8) and (−6,−4).

Answer 1

Answer:

c=square (a^2+b^2)

c=square (-6--9)^2+(-4--8)^2

Step-by-step explanation:

Answer 2

Answer:

$l(AB)=5\ units$

is the distance between the point A and point B.

Step-by-step explanation:

Let

A ≡ (x₁, y₁) ≡ (-9 , -8 )

B ≡ (x₂, y₂) ≡ (-6 , -4 )

Now by Pythagoras  Distance formula we have

a² + b² = c²

$l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}\\\\l(AB) = \sqrt{((-6--9)^{2}+(-4--8)^{2} )}\\\\l(AB)=\sqrt{(3)^{2}+(4)^{2} }\\\\l(AB) =\sqrt{25} \\\\l(AB) = 5\ units$