F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
c
Step-by-step explanation:
Step-by-step explanation:
Go 2.5 units to the right from the origin (0,0) for your x coordinate
Go 2.5 units down from the origin (0,0) for your y coordinate
Where the lines meet is your point.
- Square <em>:</em><em>4</em><em> </em><em>sides</em><em>,</em><em>each</em><em> </em><em>side</em><em> </em><em>9</em><em>0</em><em> </em><em>degrees</em><em> </em><em>.</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>:each angle is 90 degrees
: 4 diagonals
- Rectangle: 4 sides..4 angles..2 diagonals..
- Rhombus : <u>4</u><u> </u><u>sides</u><u>.</u><u>.</u><u>2</u><u> </u><u>angles</u><u>.</u><u>.</u><u>.</u><u>2</u><u> </u><u>diagonals</u><u>.</u><u>.</u>
- Parallelogram : 4 sides..4 angles..2 diagonals..
- Quadrilateral: 4 sides...4 angles...4 diagonals..
<em>If</em><em> </em><em>this</em><em> answer</em><em> helps</em><em><u> you</u></em><em><u> plz</u></em><em><u> mark</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u>.</u></em><em><u>.</u></em>
Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t = 
t₁ =
= - 5
t₂ =
= 6
Since time can be negative, it took t = 6s for Rose to hit the water.