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3241004551 [841]
3 years ago
15

A consumer believes that a certain potato chip maker is putting fewer chips in their regular bags of chips than the advertised a

mount of 12 ounces. In order to test the null hypothesis that the average chip weight is 12 ounces per bag vs. the alternative hypothesis that the average chip weight is less than 12 ounces per bag, a random sample of 49 bags were selected. The resulting data produced a p - value of 0.136.(a) At a 5% level of significance, should the null hypothesis be rejected? (Type: Yes or No):(b) At a 10% level of significance, should the null hypothesis be rejected? (Type: Yes or No): In a statistical test of hypotheses, saying that ''the evidence is statistically significant at the .05 level'' meansA. the p - value is at least .05.B. the p - value is less than .05.C. ? is more than .25.D. ?=.10.
Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

a) No

b) No

c) P value is more than 0.05.  

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 12 ounces

Sample size, n = 49

P-value = 0.136

First, we design the null and the alternate hypothesis

H_{0}: \mu = 12\text{ ounces}\\H_A: \mu < 12\text{ ounces}

We use One-tailed z test to perform this hypothesis.

a) Alpha, α = 0.05

Since, p-value > α,

The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.

b) Alpha, α = 0.10

Since, p-value > α,

The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.

c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.

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Answer:

''The median for the students is 2 and the median for the teachers is 3'' is the right option which compares the medians of the data.

Step-by-step explanation:

Data for students from the dot plot in order

0,\:0,\:1,\:1,\:1,\:1,\:2,\:2,\:2,\:2,\:2,\:2,\:2,\:3,\:3,\:3,\:3,\:3,\:4,\:4

Calculating Median for students:

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As you can see, we do not have just one middle number but we have a pair of middle numbers i.e. 2 and 2, so the median is the average of these two numbers:

Median = (2+2)/2

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Data for teachers from the dot plot in order

0, 1, 1, 1, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 8

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Read 2 more answers
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mars1129 [50]

Answer:

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

The sum of the squares of these roots is \frac{-3}{2}

Step-by-step explanation:

The given quadratic equation is 8x^2+12x-14 has two real roots.

To find the roots .

8x^2+12x-14=0

Dividing the above equation by 2

\frac{1}{2}(8x^2+12x-14)=\frac{0}{2}

4x^2+6x-7=0

For quadratic equation ax^2+bx+c=0 the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Where a and b are coefficents of x^2 and x respectively, c is a constant.

For given quadratic equation

a=4, b=6, c=-7

x=\frac{-6\pm\sqrt{6^2-4(4)(-7)}}{2(4)}

=\frac{-6\pm\sqrt{36+112}}{8}

=\frac{-6\pm\sqrt{148}}{8}

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x=\frac{(-3\pm\sqrt{37})}{4}

The real roots are

x=\frac{(-3+\sqrt{37})}{4} and x=\frac{(-3-\sqrt{37})}{4}

Now to find the sum of the squares of these roots

\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}

=\frac{-6}{4}

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\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}

Therefore the sum of the squares of these roots is \frac{-3}{2}

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