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Evgesh-ka [11]
3 years ago
6

Will mark brainliest!! Determine the slope of the line

Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

y2 - y1. over. x2 - x1

lys-0071 [83]3 years ago
3 0

Answer:

0.5

Step-by-step explanation:

Slope (m) =  ΔY ΔX =  1 /2 = 0.5

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50 yellow golf balls to 45 red golf balls what is the ratio
coldgirl [10]
The answer is 50:45 because 50 red golf balls to 45 golf balls. If you do 45:50 than that's the other way around you have to answer it exactly as it says
5 0
4 years ago
Hiii please help i’ll give brainliest thanks
Dima020 [189]

Answer:

coefficient is the term in front of the value

Hence the second term is 5b which means the value is 5

5 0
3 years ago
Find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)
Murljashka [212]

Answer:

Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

Step-by-step explanation:

We need to find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

Endpoints of a diameter A(−6, 3) and B(4, 7)

The general equation of circle is: (x-h)^2+(y-k)^2=r^2

Where r is radius and (h,k) is centre of circle.

Finding centre of circle

The midpoint of diameter is centre of circle.

So, finding midpoint of A(−6, 3) and B(4, 7)

The formula used is: Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

We have x_1=-6, y_1=3, x_2=4, y_2=7

Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\Midpoint=(\frac{-6+4}{2} ,\frac{3+7}{2} )\\Midpoint=(\frac{-2}{2} ,\frac{10}{2} )\\Midpoint=(-1 ,5)

So, we get Midpoint (x,y)=(-1,5)

Finding radius of circle

Radius of circle can be found by first finding diameter using distance formula and then divide it by 2.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\Distance=\sqrt{(4-(-6))^2+(7-3)^2} \\Distance=\sqrt{(4+6)^2+(7-3)^2} \\Distance=\sqrt{(10)^2+(4)^2} \\Distance=\sqrt{100+16}\\Distance=\sqrt{116}\\Distance = 10.77

So, Diameter = 10.77

Radius = Diameter/2 = 5.38

Equation of circle

Equation of circle having centre(-1,5) and radius r = 5.38 is:

(x-h)^2+(y-k)^2=r^2\\(x-(-1))^2+(y-5)^2=(5.38)^2\\(x+1)^2+(y-5)^2=28.94

So, Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

4 0
3 years ago
Mean (ul) = 510 and standard deviation (0) = 80
aliina [53]

Answer:

Step-by-step explanation:

1.  Use a calculator with distribution functions here.  We're interested in finding the area under the standard normal curve to the right of 590, given that the mean is 510 and the standard deviation is 80.  Note that 590 = 510 + 80, meaning that 590 is 1 standard deviation above the mean.

According to the Empirical Rule, 68% of data under a standard normal curve lies within 1 standard deviation of the mean.  The area from the extreme left of this curve to x = 510 is 0.500, and the additional area under the curve from 510 to 590 is 34% of the total area, or 0.340.

Thus, the desired area is 0.500 + 0.340 = 0.840.  This represents the desired probability.

2.  What percentile is a score of 750?  Find the number of standard deviations to the left of 750:

                  750 - 510

z-score = ------------------- = 24/8 = 3.00

                         80

The desired percentile is the area to the left of z = 3.00.  Using a calculator, we find this area to be 0.9987.  That 750 score is in the 99+ percentile.

3 0
3 years ago
The ancient greeks required a straightedge and a protractor to construct a perpendicular bisector for a given line segment.
mafiozo [28]

Answer: False

Step-by-step explanation:

The ancient Greeks required a straightedge and a compass to construct a perpendicular bisector for a given line segment.

They made perpendicular bisector by using following steps.

Let given a line segment XY, then to construct the perpendicular bisector.



Step 1)Draw a circle centered at X and passing through point Y.


Step2)Draw a circle centered at Y and passing through point B.


Step3)The two circles intersect at two points (above and below of line segment XY). Draw the line through these two points. This line is the perpendicular bisector to XY.

7 0
4 years ago
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