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agasfer [191]
4 years ago
11

Which shows the expressions rewritten with a common denominator? x-5/x+3 and 4/x-3

Mathematics
1 answer:
Maru [420]4 years ago
3 0

Answer:

x-5/x+3  = (x² - 2x  -15)/(x² - 9)  

4/x-3 = (4x + 12)/(x² - 9)

Step-by-step explanation:

Points to remember

(a + b)(a - b) = a² - b²

It is given two expression,

x-5/x+3 and 4/x-3

<u>To find the common denominator</u>

The first denominator is (x + 3) and the second denominator is (x - 3)

The common denominator is (x + 3)(x -3)

x-5/x+3 can be written as,

(x-5)/(x+3) * (x - 3)/(x - 3)

= (x² -5x + 3x -15)/(x² - 9)

= (x² - 2x  -15)/(x² - 9)

4/(x - 3) can be written as,

4/(x - 3) * (x + 3)(x + 3)

 = 4(x + 3)/(x - 3)(x + 3)

 = (4x + 12)/(x² - 9)

Therefore x-5/x+3 and 4/x-3 in common denominator is,

x-5/x+3  = (x² - 2x  -15)/(x² - 9)  

4/x-3 = (4x + 12)/(x² - 9)

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3 0
3 years ago
How do solve or simplify this?<br>10/9*7/5
Nostrana [21]
1. Are you asking how to solve or simplify?

If so, the answer is simple.

PEMDAS 
Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.

10 divided by 9 times 7 divided by 5.

9 times 7 first. 63 so lets re word the equation

10 divided by 63 divided by 5

now its 6.3 divided by 5

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Am I correct with either?
6 0
4 years ago
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Help with those three please!!
Scilla [17]

Answer:

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Part 2) Option C. minimum

Part 3) Option A. (4,-4)

Part 4) Option B. (2,0) and (6,0)

Step-by-step explanation:

we have

f(x)=x^{2}-8x+12

Part 1) What is the axis of symmetry of the parabola described by the equation above?

we know that

The equation above is a vertical parabola open upward

The axis of symmetry is the x-coordinate of the vertex

Find the vertex of the parabola (convert the equation in vertex form)

f(x)-12=x^{2}-8x

f(x)-12+16=x^{2}-8x+16

f(x)+4=x^{2}-8x+16

f(x)+4=(x-4)^{2}

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The vertex of the parabola is (4,-4)

so

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Part 2) The vertex of the equation above is also

we know that

The equation above is a vertical parabola open upward

therefore

The vertex is a minimum

Part 3) What is the vertex of the parabola described by the equation above

we know that

The equation of the parabola into vertex form is equal to

f(x)=(x-4)^{2}-4

therefore

The vertex of the parabola is (4,-4)

Part 4) What are the  x-intercepts of the parabola described by the equation above

we know that

The x-intercepts are the values of x when the value of y is equal to zero

so

f(x)+4=(x-4)^{2}

f)x)=0

so

4=(x-4)^{2}

take square root both sides

(x-4)=(+/-)2

x=4(+/-)2

x=4(+)2=6

x=4(-)2=2

therefore

The x-intercepts are

(2,0) and (6,0)

7 0
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zepelin [54]
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mrs_skeptik [129]

Answer:

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Step-by-step explanation:

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