The NR of -2 is -0.5. So you would need to subtract -2.5
Answer:
What do you mean by this?
Answer:
Step-by-step explanation:
If the value of the TV decreases by 14% each year, then the rate is exponential.
We would apply the formula for exponential growth which is expressed as
A = P(1 + r/n)^ nt
Where
A represents the price of the TV after t years.
n represents the periodic rate at which the decrease is calculated.
t represents the number of years.
P represents the initial price of the TV.
r represents rate of decrease in value of the TV.
From the information given,
P = $1500
r = 14% = 14/100 = 0.14
n = 1
A = y
Therefore, the function would be
y = 1500(1 + 0.14/1)^ 1 × t
y = 1500(1.14)^t
Answer:
for ![x\geq0](https://tex.z-dn.net/?f=x%5Cgeq0)
and
for ![x](https://tex.z-dn.net/?f=x%20%3C0)
Step-by-step explanation:
Remember that the CDF of an exponental random variable is given by
![F(x,\lambda) = \left \{ {{1-e^{\lambda x} \ \ \ \ \ x\geq 0} \atop {0} \ \ \ \ \ \ \ \ \ \ \ x](https://tex.z-dn.net/?f=F%28x%2C%5Clambda%29%20%3D%20%5Cleft%20%5C%7B%20%7B%7B1-e%5E%7B%5Clambda%20x%7D%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%20x%5Cgeq%200%7D%20%5Catop%20%7B0%7D%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20x%3C0%7D%20%20%5Cright.)
where
is the parameter. In this case
so, for this case
![F(x,\lambda) = \left \{ {{1-e^{2x} \ \ \ \ \ x\geq 0} \atop {0} \ \ \ \ \ \ \ \ \ \ \ x](https://tex.z-dn.net/?f=F%28x%2C%5Clambda%29%20%3D%20%5Cleft%20%5C%7B%20%7B%7B1-e%5E%7B2x%7D%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%20x%5Cgeq%200%7D%20%5Catop%20%7B0%7D%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20x%3C0%7D%20%20%5Cright.)