Answer:
(x + 1)^2 + (y - 4)^2 = 8
Step-by-step explanation:
Midpoint of the diameter is the centre
So....Centre coordinates are ((-3+1)÷2 ; (2+6)÷2) = (-1;4)
Calculate the radius of the circle....
Radius = square root of [(-1+3)^2 + (4-2)^2]
;Radius = square root of 8
Then substitute the x-coordinate of the centre into the first slot....then the y-coordinate into the second slot and the radius(squared) into last slot of the equation......;
(x + 1)^2 + (y - 4)^2 = 8
(Can't really explain it... hopefully these steps can help you.. maybe I'm just too lazy..)
2h^3j^-3k^4
-----------------
3jk
2h^3k^4
= -------------
3j^4k
2h^3k^3
= --------------
3j^4
Answer:
The correct answer is option B. 17
Step-by-step explanation:
It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°
<u>To find the value of m</u>
From the figure we can see that, triangle WYZ is an isosceles triangle.
ZW = ZY
Then <YXZ = <WXZ = 90°
It is given ∠YXZ = (6m – 12)°
(6m – 12)° = 90°
6m = 90 + 12 = 102
m = 102/6 = 17
Therefore the value of m = 17
The correct answer is option B. 17
Answer:
y = 9
Step-by-step explanation: this is because when x is 5 and is multiplied by -6 u get -30. from there u substratc -30 from -57 and get -27. so y is 9
