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ELEN [110]
3 years ago
6

Two equations are given below:

Mathematics
1 answer:
34kurt3 years ago
6 0

(-5,-3) since plug in a=b-2 into the first equation and then solver for b.  You get -3.-3-2=-5 which is a


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In how many ways can a teacher arrange 5 students in the front row of a classroom if there are 20 students in the class
liraira [26]

Answer:

4 times

Step-by-step explanation:

because there's only enough space for that many in each row.

3 0
3 years ago
Solve 56x+23930=97x+16693 by substitution.
Tomtit [17]

Answer:

You can't really use substitution for this problem b/c there is nothing to substitute.

Step-by-step explanation:

56x+23930=97x+16693

Subtract 23930 from both sides:

56x+23930-23930=97x+16693-23930

simplify:

56x=97x-7237

subtract 97x from both sides:

56x-97x=97x-7237-97x

Simplify:

-41x=-7237

Divide both sides by -41

-41x/-41=-7237/-41

Simplify:

x=7237/41

3 0
3 years ago
Nathan finds a backpack at kitt’s that is regularly $84.99,but is on sale for 1/3 off.the same backpack is regularly 72.99 at re
timama [110]
The $72.99 backpack is a better choice to buy because
The $84.99 backpack for 1/3 off is approximately $28.3299 (about $28.33)
And the $72.99 backpack for 25% off is $18.2475 (about $18.25)
So since $18.25 < $28.33, the $72.99 backpack has a cheaper price.
7 0
3 years ago
2. Find the stationary points for the function
vovikov84 [41]

Answer & step-by-step explanation:

Stationary points are the points where the first derivative is equal to zero.

Let's calculate it using the power rule (exponent comes forward, decrease exponent by 1) and the fact that the derivative is a linear operation (that is D[a\ f(x) + b\ g(x)] = a Df(x) + b Dg(x))

The first derivative is then

y' = \frac13 (3x^2) - \frac12 (2x) -6 = x^2-x-6 = (x+2)(x-3)

Note that the last passage is not strictly needed, but it's really helpful to find stationary points, when in this next passage we set it equal to zero. Alternatively, you can use the quadratic formula if you can pull the factors out of your head right away.

y'=0 \rightarrow (x+2)(x-3) = 0 \implies x=-2  || x=3

These two point could be maxima, minima, or inflection points. To check them you can either see how the sign of the first derivative goes, or check the sign of the second derivative, as you're required.

The rules states that if the second derivative evaluated in that point is negative we have a maximum, if it's positive we have a minimum, and if we have a zero we keep derivating until we get a non-zero  value.

In our case, the second derivative we get by calculating the derivative again and we get y'' = 2x-1 . Evaluating it at both points we get

y''(-2) = 2(-2)-1 = -5\\y''(3) = 2(3) -1 = 5

so -2 is a maximum and 3 is a minimum.

5 0
2 years ago
Read 2 more answers
Simplify this expression! (27)^-2/3
mariarad [96]
The answer is 243
so first it is 1/27^2/3 
then you multiply 
5 0
3 years ago
Read 2 more answers
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