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EleoNora [17]
3 years ago
13

Evaluate 5p+cd when c=1/5 and d=15

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer: If solving for P it is p = -3/5

If you are just wanting the equation it is 5p+3


Step-by-step explanation: Plug in c and d into 5p+cd

You get 5p+(1/5)(15)

Once done with the math it is 5p+3


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STION 1
Lorico [155]

Answer:

1.1.1- Michael has 200 lovebirds in total

1.1.2- There are 40 birds in each cage

1.1.3- 120/80 = 3/2

Step-by-step explanation:

120+80=200

200÷5=40

120÷40=3, 80÷40=2

7 0
3 years ago
Need help please !!!
blsea [12.9K]

Answer:

option C is the correct answer

Step-by-step explanation:

The trigonometric equation you are using has a general form

y = A* tan w*(x - r)

Where

A is the amplitude of the function

w is the frequency rad/s

r  is the phase shift

In your case

A = -2

The frequency is

w = (2*pi)/period

period = pi/4

w = 8

r = -pi/2

y = -2* cos 8*(x + pi/2)

7 0
3 years ago
Can someone help me with this one question?
kondor19780726 [428]

Answer:

no...

Step-by-step explanation:

3 0
3 years ago
What is 5÷98<br><img src="https://tex.z-dn.net/?f=5%20%5Cdiv%2098" id="TexFormula1" title="5 \div 98" alt="5 \div 98" align="abs
saveliy_v [14]
The answer is 0.05102
3 0
3 years ago
Someone please help or i’ll be failing geometry this year
Vlad [161]

Step-by-step explanation:

I don't know what constructions you were taught.

a "similar" triangle is a triangle with exactly the same angles as the other triangle, but the lengths of all sides are stretched or shortened by the same scaling factor f.

by saying 1:2 she means the second triangle should have sides with twice the lengths of the first triangle (f=2).

and the extra challenge - same basic thing. she allows you to pick one of the two triangles as reference. and then you need to draw a third triangle (again with the same angles) with the side lengths extended by the scaling factor f of 4/3.

I would draw the triangles right on top of each other with the same starting corner (let's call it A) for all 3.

we would get the triangles ABC, AMN and AXY.

the points B and C would be then halfway on AM and AN.

and M and N would then a bit before X and Y on AX and AY.

the beauty is, you only need to construct 2 sides of every new triangle down to the new endpoints. the third side is automatically scaled correctly, and you only need to connect these new endpoints.

let's assume you draw a triangle (just very simple) ABC with all side lengths being 3. so, AB=3, AC=3, BC=3.

now you draw AMN by extending AB and AC to a side length of 6 (f=2) creating M and N, and you connect M and N.

and then you can create the third triangle AXY by extending AM and AN by a factor of 4/3 to side lengths of 8 (4/3 × 6 = 8) creating new end points X and Y. and you connect X and Y.

and that is it. all 3 triangles are similar (the same angles), and all sides of a triangle have the same length ratio to the sides of the other triangle(s).

4 0
2 years ago
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