A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
y = 1/3
Step-by-step explanation:
<u>Step 1: Factor</u>
9y^2 - 6y + 1 = 0
(3y - 1)(3y - 1) = 0
(3y - 1)^2 = 0
<u>Step 2: Solve for y</u>
3y - 1 + 1 = 0 + 1
3y / 3 = 1 / 3
y = 1/3
Answer: y = 1/3
I believe the sum of the root is: -3/2
And the product of the root is: 0
I hope this helps and have a great week :)
Answer:
6
Step-by-step explanation:
To answer this simply subtract 7 from 13 to find the answer.
13-7=6
Hope this helps!
If not, I am sorry.
A = L^2
A = L^2 = 2^2 + 4^2 (Pythagorean’s theorem)
A = L^2 = 20
Therefore the area of the square is 20 units square.
