Correlational study is used to show the type of association or relationship which exists between two or more variables using statistical analysis. Ken's research shows that <em>there</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>relationship</em><em> </em><em>between</em><em> </em><em>childhood</em><em> </em><em>anger</em><em> </em><em>management</em><em> </em><em>and</em><em> </em><em>adult</em><em> </em><em>earning</em><em>.</em><em> </em>
- According to Ken's research, learning how to control anger leads to making more income during adulthood. This signifies a positive relationship between good anger management in childhood and earning made during adulthood.
- Similarly poor anger management in childhood leads is associated with low earning during adulthood.
- Hence, Ken's research shows that there is a relationship between <em>childhood</em><em> </em><em>anger</em><em> </em><em>management</em><em> </em><em>and</em><em> </em><em>adult</em><em> </em><em>earnings</em><em>.</em><em> </em>
<em>Learn</em><em> </em><em>more</em><em> </em><em>:</em><em> </em><em>brainly.com/question/17561092?referrer=searchResults</em>
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
Answer:
Option C
Explanation:
Brent will opt to work with an individual who has the desired characteristics to meet the work requirement and could also go along with efficient team building. Thus, in case if both Ken and Darwin have similar characteristics, then Brent would prefer to work with both the person irrespective of their color. Physical characteristics will not impact Brent decision for choosing one amongst the two.
Hence, option C is correct
The answer is D.
Tertiary consumers eat primary and secondary consumers. Therefore, carnivores that eat other carnivores are called tertiary consumers. An example of primary consumers are rabbits and giraffes. An example of secondary consumers are snakes and rats.