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elixir [45]
3 years ago
8

)What item is at the front of the list after these statements are executed?

Computers and Technology
1 answer:
Dominik [7]3 years ago
4 0

Answer:

C.Rudy

Explanation:

A deque waitingLine is created.Then Jack is added to front of the deque first.After that Rudy is added to the front of the deque.AFter that Larry and sam are inserted at the back.So the last item inserted at the front is front of the deque.So Rudy was the last item inserted at the front.

Hence we conclude that the answer is Rudy.

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Question 12
AlladinOne [14]

Which is a multicast address ?

ans: 241.2.2.1

6 0
2 years ago
Look at the options below. Which one is a simulation?
Elena-2011 [213]

Im going to guess the 2nd one.

The 1st one just shows how trees can make ____ and then goes to water, the sun, then the rain but it CAN be used as one.

The 2nd one seems to explain the best it can show about weather, water, landforms, the sun, and seems like a better one to choose.

5 0
3 years ago
75,15,25,5,15 what's next
Fittoniya [83]

Answer:

3

Explanation:

The sequence seems to follow a 2-step pattern.

1)Divide the first number by 5 to get the second number.

2)Add 10 to the second number to get the third number.

75/5 = 15

15 + 10 = 25

25/5 = 5

5 + 10 = 15

---> 15/5 = [3] (Answer)

3 0
3 years ago
I need help 50 points and brainless if you answer
nata0808 [166]

Answer:

50

var X gets passed into the rectangle function, which I assume would set the x and y coordinates to what the var's have already been set to.

4 0
3 years ago
Read 2 more answers
3. An organization wants to use the private network number 192.168.90.0 across four subnets. The maximum number of hosts that ex
lesya [120]

Answer:

The correct answer is: 255.255.255.192.

Explanation:

A subnet mask complements an Internet Protocol (IP). Thanks to subnet masks IP addresses can be identified because they seem to be all the same but the subnet mask avoids confusion. If four subnets are to be created for the IP 192.168.90.0 3 bits of that IP must be used to create the subnet resulting in 255.255.255.192. Then:

  • <em>Number of subnets</em>: 2^{3} - 2 = 6
  • <em>Number of hosts per subnet</em> = 2^{5} -2  = 30
3 0
3 years ago
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