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Tpy6a [65]
2 years ago
11

The tax rate is 7.5% what is the tax on $110 round to the nearest hundredth or tenth

Mathematics
1 answer:
Sladkaya [172]2 years ago
3 0
$100 x 0.075 = $8.25

answer:

$ 8.25 <span>is the tax on $110 round to the nearest hundredth 

</span>$ 8.3 is the tax on $110 round to the nearest tenth
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Reasoning : Why is the numerator greater than
Digiron [165]

Answer:

See the explanation

Step-by-step explanation:

When the numerator is less than the denominator, the result is always less than 1, that is 0. something and this will give a percentage less than 100, but when the numerator is greater than the denominator, th result is greater than 1, and any figure greater than 1 gives a percentage that is greater than 100

example

Numerator >Denominator

=4/2*100

=2*100

=200%

Numerator <Denominator

=2/4*100

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2 years ago
Saffron is a powder made from crocus flowers and is used in the manufacturing of perfume. Some 8,000 crocus flowers are required
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16/2=8
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Which graph represents y=^3sqrt x-5​
Lelechka [254]

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4

Step-by-step explanation:

Graph 4

7 0
3 years ago
Use the chart to estimate the population density of Romania in 1997. Round to the nearest person.
STALIN [3.7K]

The population density of Romania in 1997 given its area and the population is 95 people per square km.

<h3>What is the population density?</h3>

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brainly.com/question/3704320

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5 0
1 year ago
To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t
ivolga24 [154]

Answer:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:  

Null hypothesis:\mu \leq 100  

Alternative hypothesis:\mu > 100  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic calculated for this case  t_{calc}= 1.42

The degrees of freedom are given by:

df=n-1=30-1=29  

Now we can find the p value using tha laternative hypothesis and we got:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0
3 years ago
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