Answer:
genotypic ratio = 2:2
Explanation:
We were being told that when Mendel crossed yellow- seeded and green- seeded pea plants, all the offspring were yellow seeded.
This implies that the Yellow seed trait masked the green seed trait in the F1 generation. The best defination that can be deduced is that;
the yellow-seeded plants are homozygous dominant &
the green-seed pea plants are homozygous recessive
So, let yellow- seeded pea plants= YY
and green- seeded pea plants= gg
i.e YY × gg
| Y | Y
g | Yg | Yg
g | Yg | Yg
F₁ = (Yg, Yg, Yg, Yg,) All the offspring were heterozygous yellow seeded plant.
Now, when he crossed the F₁ heterozygous yellow seeded plant with the green- seeded plants; we will have the following result
i.e Yg × gg
| Y | g
g | Yg | gg
g | Yg | gg
F₂ = (Yg, Yg, gg, gg)
The F₂ generation would have genotypes of (Yg, and gg) and a genotypic ratio of 2:2
Answer:
Option (B) Ethylene gas is a chemical signal through which ripening fruits trigger the ripening process in other fruits.
Explanation:
The ethylene hormone triggers the ripening process of fruit. However, in order to slow down the ripening process the action of ethylene is to be blocked. All fruits are capable to produce ethylene up to a certain level after which they start ripening. There are some classes of fruits that respond to the external ethylene such as apple, mango, tomato etc.
Hence, option B is correct
Answer:
high efficiency particulate air
Explanation:
<span>92 elements have been found to occur in nature
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Answer:
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