Question

According to m&ms web site, each package of the milk chocolate candies typically contain 14% brown, 13% red, 14% yellow, 16% green, 24% blue, and 20% orange m&ms. you go to the store and buy a standard-sized package. when you open it, you find that it contains 51 m&ms, distributed as follows: color brown red yellow green blue orange frequency 8 4 10 7 11 11 over the long run, you know that the probability of selecting a blue or an orange m&m will be 44% because these outcomes are: finite. disjoint. discrete. none of the answer choices is correct.

Answer 1

Answer: Disjoint

Step-by-step explanation: Selecting specific colors in a m&m's pack is disjoint because the events cannot occur at the same time, i.e., when you take one m&m's, it can be blue and orange at the same time.

To determine the probability of disjoint or mutually exclusive events, you can find their probability by adding the probability of each event.

In the question, it is asked the probability of selecting a blue or an orange.

Probability of a blue:

P(b) = $\frac{11}{51}$

Probability of an orange:

P(o) = $\frac{11}{51}$

Probability of one OR the other:

P(b OR o) = P(b) + P(o)

P(b OR o) = $\frac{11}{51} + \frac{11}{51}$

P(b OR o) = $\frac{22}{51}$

P(b OR o) ≈ 0.44 or 44%

The probability of blue or orange m&m's is 44%, and the events are disjoint.

Answer 2

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